David and Jean had the same number of sweets. After Jean gave away 19 sweets and David gave away 50 sweets, Jean had 2 times as many sweets as David. How many sweets did each of them have at first?
| |
David |
Jean |
| Before |
1 u + 50 |
2 u + 19 |
| Change |
- 50 |
- 19 |
| After |
1 u |
2 u |
The number of sweets that David and Jean had at first is the same.
2 u + 19 = 1 u + 50
2 u - 1 u = 50 - 19
1 u = 31
1 u = 31 ÷ 1 = 31
Number of sweets that each of them had at first
= 1 u + 50
= 31 + 50
= 81
Answer(s): 81
