David and Diana had the same number of sweets. After Diana gave away 18 sweets and David gave away 54 sweets, Diana had 3 times as many sweets as David. How many sweets did each of them have at first?
| |
David |
Diana |
| Before |
1 u + 54 |
3 u + 18 |
| Change |
- 54 |
- 18 |
| After |
1 u |
3 u |
The number of sweets that David and Diana had at first is the same.
3 u + 18 = 1 u + 54
3 u - 1 u = 54 - 18
2 u = 36
1 u = 36 ÷ 2 = 18
Number of sweets that each of them had at first
= 1 u + 54
= 18 + 54
= 72
Answer(s): 72
