Simon and Marion had the same number of lollipops. After Marion gave away 12 lollipops and Simon gave away 45 lollipops, Marion had 4 times as many lollipops as Simon. How many lollipops did each of them have at first?
| |
Simon |
Marion |
| Before |
1 u + 45 |
4 u + 12 |
| Change |
- 45 |
- 12 |
| After |
1 u |
4 u |
The number of lollipops that Simon and Marion had at first is the same.
4 u + 12 = 1 u + 45
4 u - 1 u = 45 - 12
3 u = 33
1 u = 33 ÷ 3 = 11
Number of lollipops that each of them had at first
= 1 u + 45
= 11 + 45
= 56
Answer(s): 56
