Sam and Xylia had the same number of lollipops. After Xylia gave away 18 lollipops and Sam gave away 42 lollipops, Xylia had 2 times as many lollipops as Sam. How many lollipops did each of them have at first?
| |
Sam |
Xylia |
| Before |
1 u + 42 |
2 u + 18 |
| Change |
- 42 |
- 18 |
| After |
1 u |
2 u |
The number of lollipops that Sam and Xylia had at first is the same.
2 u + 18 = 1 u + 42
2 u - 1 u = 42 - 18
1 u = 24
1 u = 24 ÷ 1 = 24
Number of lollipops that each of them had at first
= 1 u + 42
= 24 + 42
= 66
Answer(s): 66
