Xavier and Yen had the same number of sweets. After Yen gave away 13 sweets and Xavier gave away 41 sweets, Yen had 2 times as many sweets as Xavier. How many sweets did each of them have at first?
| |
Xavier |
Yen |
| Before |
1 u + 41 |
2 u + 13 |
| Change |
- 41 |
- 13 |
| After |
1 u |
2 u |
The number of sweets that Xavier and Yen had at first is the same.
2 u + 13 = 1 u + 41
2 u - 1 u = 41 - 13
1 u = 28
1 u = 28 ÷ 1 = 28
Number of sweets that each of them had at first
= 1 u + 41
= 28 + 41
= 69
Answer(s): 69
