Xavier and Shiyun had the same number of chocolate bars. After Shiyun gave away 21 chocolate bars and Xavier gave away 39 chocolate bars, Shiyun had 3 times as many chocolate bars as Xavier. How many chocolate bars did each of them have at first?
| |
Xavier |
Shiyun |
| Before |
1 u + 39 |
3 u + 21 |
| Change |
- 39 |
- 21 |
| After |
1 u |
3 u |
The number of chocolate bars that Xavier and Shiyun had at first is the same.
3 u + 21 = 1 u + 39
3 u - 1 u = 39 - 21
2 u = 18
1 u = 18 ÷ 2 = 9
Number of chocolate bars that each of them had at first
= 1 u + 39
= 9 + 39
= 48
Answer(s): 48
