Pierre and Marion had the same number of mochi balls. After Marion gave away 22 mochi balls and Pierre gave away 40 mochi balls, Marion had 3 times as many mochi balls as Pierre. How many mochi balls did each of them have at first?
| |
Pierre |
Marion |
| Before |
1 u + 40 |
3 u + 22 |
| Change |
- 40 |
- 22 |
| After |
1 u |
3 u |
The number of mochi balls that Pierre and Marion had at first is the same.
3 u + 22 = 1 u + 40
3 u - 1 u = 40 - 22
2 u = 18
1 u = 18 ÷ 2 = 9
Number of mochi balls that each of them had at first
= 1 u + 40
= 9 + 40
= 49
Answer(s): 49
