Tim and Xuan had the same number of sweets. After Xuan gave away 12 sweets and Tim gave away 39 sweets, Xuan had 4 times as many sweets as Tim. How many sweets did each of them have at first?
| |
Tim |
Xuan |
| Before |
1 u + 39 |
4 u + 12 |
| Change |
- 39 |
- 12 |
| After |
1 u |
4 u |
The number of sweets that Tim and Xuan had at first is the same.
4 u + 12 = 1 u + 39
4 u - 1 u = 39 - 12
3 u = 27
1 u = 27 ÷ 3 = 9
Number of sweets that each of them had at first
= 1 u + 39
= 9 + 39
= 48
Answer(s): 48
