Howard and Shannon had the same number of chocolate bars. After Shannon gave away 14 chocolate bars and Howard gave away 51 chocolate bars, Shannon had 2 times as many chocolate bars as Howard. How many chocolate bars did each of them have at first?
| |
Howard |
Shannon |
| Before |
1 u + 51 |
2 u + 14 |
| Change |
- 51 |
- 14 |
| After |
1 u |
2 u |
The number of chocolate bars that Howard and Shannon had at first is the same.
2 u + 14 = 1 u + 51
2 u - 1 u = 51 - 14
1 u = 37
1 u = 37 ÷ 1 = 37
Number of chocolate bars that each of them had at first
= 1 u + 51
= 37 + 51
= 88
Answer(s): 88
