Warren had some coins. 45% of his coins were made up of 50-cent coins which was equal to the number of $1 coins. The rest of the coins were made up of 10-cent coins. Given that Warren had $43 more 50-cent coins than 10-cent coins, how many coins did Warren have altogether?
| |
10-cent |
50-cent |
$1 |
Total |
| Number |
2 u |
9 u |
9 u |
20 u |
| Value |
10 |
50 |
100 |
|
| Total value |
20 u |
450 u |
900 u |
|
45% =
45100 =
920The number of 50-cent coins and $1 coins is the same.
Number of 10-cent coins
= 20 u - 9 u - 9 u
= 2 u
$1 = 100¢
$43 x 100 = 43 x 100 = 4300¢
Number of more 50-cent coins than 10-cent coins
= 450 u - 20 u
= 430 u
430 u = 4300
1 u = 4300 ÷ 430 = 10
Total number of coins that Warren had
= 2 u + 9 u + 9 u
= 20 u
= 20 x 10
= 200
Answer(s): 200
