Gabriel had some coins. 40% of his coins were made up of 50-cent coins which was equal to the number of $1 coins. The rest of the coins were made up of 20-cent coins. Given that Gabriel had $16 more 50-cent coins than 20-cent coins, how many coins did Gabriel have altogether?
|
20-cent |
50-cent |
$1 |
Total |
Number |
1 u |
2 u |
2 u |
5 u |
Value |
20 |
50 |
100 |
|
Total value |
20 u |
100 u |
200 u |
|
40% =
40100 =
25The number of 50-cent coins and $1 coins is the same.
Number of 20-cent coins
= 5 u - 2 u - 2 u
= 1 u
$1 = 100¢
$16 x 100 = 16 x 100 = 1600¢
Number of more 50-cent coins than 20-cent coins
= 100 u - 20 u
= 80 u
80 u = 1600
1 u = 1600 ÷ 80 = 20
Total number of coins that Gabriel had
= 1 u + 2 u + 2 u
= 5 u
= 5 x 20
= 100
Answer(s): 100