Seth had some coins. 36% of his coins were made up of 50-cent coins which was equal to the number of $1 coins. The rest of the coins were made up of 10-cent coins. Given that Seth had $76 more 50-cent coins than 10-cent coins, how many coins did Seth have altogether?
| |
10-cent |
50-cent |
$1 |
Total |
| Number |
7 u |
9 u |
9 u |
25 u |
| Value |
10 |
50 |
100 |
|
| Total value |
70 u |
450 u |
900 u |
|
36% =
36100 =
925The number of 50-cent coins and $1 coins is the same.
Number of 10-cent coins
= 25 u - 9 u - 9 u
= 7 u
$1 = 100¢
$76 x 100 = 76 x 100 = 7600¢
Number of more 50-cent coins than 10-cent coins
= 450 u - 70 u
= 380 u
380 u = 7600
1 u = 7600 ÷ 380 = 20
Total number of coins that Seth had
= 7 u + 9 u + 9 u
= 25 u
= 25 x 20
= 500
Answer(s): 500
