Zane had some coins. 40% of his coins were made up of 50-cent coins which was equal to the number of $1 coins. The rest of the coins were made up of 10-cent coins. Given that Zane had $9 more 50-cent coins than 10-cent coins, how many coins did Zane have altogether?
| |
10-cent |
50-cent |
$1 |
Total |
| Number |
1 u |
2 u |
2 u |
5 u |
| Value |
10 |
50 |
100 |
|
| Total value |
10 u |
100 u |
200 u |
|
40% =
40100 =
25The number of 50-cent coins and $1 coins is the same.
Number of 10-cent coins
= 5 u - 2 u - 2 u
= 1 u
$1 = 100¢
$9 x 100 = 9 x 100 = 900¢
Number of more 50-cent coins than 10-cent coins
= 100 u - 10 u
= 90 u
90 u = 900
1 u = 900 ÷ 90 = 10
Total number of coins that Zane had
= 1 u + 2 u + 2 u
= 5 u
= 5 x 10
= 50
Answer(s): 50
