Luis had some coins. 40% of his coins were made up of 20-cent coins which was equal to the number of $1 coins. The rest of the coins were made up of 10-cent coins. Given that Luis had $6 more 20-cent coins than 10-cent coins, how many coins did Luis have altogether?
|
10-cent |
20-cent |
$1 |
Total |
Number |
1 u |
2 u |
2 u |
5 u |
Value |
10 |
20 |
100 |
|
Total value |
10 u |
40 u |
200 u |
|
40% =
40100 =
25The number of 20-cent coins and $1 coins is the same.
Number of 10-cent coins
= 5 u - 2 u - 2 u
= 1 u
$1 = 100¢
$6 x 100 = 6 x 100 = 600¢
Number of more 20-cent coins than 10-cent coins
= 40 u - 10 u
= 30 u
30 u = 600
1 u = 600 ÷ 30 = 20
Total number of coins that Luis had
= 1 u + 2 u + 2 u
= 5 u
= 5 x 20
= 100
Answer(s): 100