Paul had some coins. 35% of his coins were made up of 50-cent coins which was equal to the number of $1 coins. The rest of the coins were made up of 10-cent coins. Given that Paul had $58 more 50-cent coins than 10-cent coins, how many coins did Paul have altogether?
|
10-cent |
50-cent |
$1 |
Total |
Number |
6 u |
7 u |
7 u |
20 u |
Value |
10 |
50 |
100 |
|
Total value |
60 u |
350 u |
700 u |
|
35% =
35100 =
720The number of 50-cent coins and $1 coins is the same.
Number of 10-cent coins
= 20 u - 7 u - 7 u
= 6 u
$1 = 100¢
$58 x 100 = 58 x 100 = 5800¢
Number of more 50-cent coins than 10-cent coins
= 350 u - 60 u
= 290 u
290 u = 5800
1 u = 5800 ÷ 290 = 20
Total number of coins that Paul had
= 6 u + 7 u + 7 u
= 20 u
= 20 x 20
= 400
Answer(s): 400