Seth had some coins. 35% of his coins were made up of 10-cent coins which was equal to the number of $1 coins. The rest of the coins were made up of 5-cent coins. Given that Seth had $6 more 10-cent coins than 5-cent coins, how many coins did Seth have altogether?
|
5-cent |
10-cent |
$1 |
Total |
Number |
6 u |
7 u |
7 u |
20 u |
Value |
5 |
10 |
100 |
|
Total value |
30 u |
70 u |
700 u |
|
35% =
35100 =
720The number of 10-cent coins and $1 coins is the same.
Number of 5-cent coins
= 20 u - 7 u - 7 u
= 6 u
$1 = 100¢
$6 x 100 = 6 x 100 = 600¢
Number of more 10-cent coins than 5-cent coins
= 70 u - 30 u
= 40 u
40 u = 600
1 u = 600 ÷ 40 = 15
Total number of coins that Seth had
= 6 u + 7 u + 7 u
= 20 u
= 20 x 15
= 300
Answer(s): 300