Warren had some coins. 45% of his coins were made up of 10-cent coins which was equal to the number of $1 coins. The rest of the coins were made up of 5-cent coins. Given that Warren had $4 more 10-cent coins than 5-cent coins, how many coins did Warren have altogether?
| |
5-cent |
10-cent |
$1 |
Total |
| Number |
2 u |
9 u |
9 u |
20 u |
| Value |
5 |
10 |
100 |
|
| Total value |
10 u |
90 u |
900 u |
|
45% =
45100 =
920The number of 10-cent coins and $1 coins is the same.
Number of 5-cent coins
= 20 u - 9 u - 9 u
= 2 u
$1 = 100¢
$4 x 100 = 4 x 100 = 400¢
Number of more 10-cent coins than 5-cent coins
= 90 u - 10 u
= 80 u
80 u = 400
1 u = 400 ÷ 80 = 5
Total number of coins that Warren had
= 2 u + 9 u + 9 u
= 20 u
= 20 x 5
= 100
Answer(s): 100
