Justin had some coins. 40% of his coins were made up of 50-cent coins which was equal to the number of $1 coins. The rest of the coins were made up of 20-cent coins. Given that Justin had $20 more 50-cent coins than 20-cent coins, how many coins did Justin have altogether?
| |
20-cent |
50-cent |
$1 |
Total |
| Number |
1 u |
2 u |
2 u |
5 u |
| Value |
20 |
50 |
100 |
|
| Total value |
20 u |
100 u |
200 u |
|
40% =
40100 =
25The number of 50-cent coins and $1 coins is the same.
Number of 20-cent coins
= 5 u - 2 u - 2 u
= 1 u
$1 = 100¢
$20 x 100 = 20 x 100 = 2000¢
Number of more 50-cent coins than 20-cent coins
= 100 u - 20 u
= 80 u
80 u = 2000
1 u = 2000 ÷ 80 = 25
Total number of coins that Justin had
= 1 u + 2 u + 2 u
= 5 u
= 5 x 25
= 125
Answer(s): 125
