Julian had some coins. 45% of his coins were made up of 50-cent coins which was equal to the number of $1 coins. The rest of the coins were made up of 20-cent coins. Given that Julian had $41 more 50-cent coins than 20-cent coins, how many coins did Julian have altogether?
|
20-cent |
50-cent |
$1 |
Total |
Number |
2 u |
9 u |
9 u |
20 u |
Value |
20 |
50 |
100 |
|
Total value |
40 u |
450 u |
900 u |
|
45% =
45100 =
920The number of 50-cent coins and $1 coins is the same.
Number of 20-cent coins
= 20 u - 9 u - 9 u
= 2 u
$1 = 100¢
$41 x 100 = 41 x 100 = 4100¢
Number of more 50-cent coins than 20-cent coins
= 450 u - 40 u
= 410 u
410 u = 4100
1 u = 4100 ÷ 410 = 10
Total number of coins that Julian had
= 2 u + 9 u + 9 u
= 20 u
= 20 x 10
= 200
Answer(s): 200