Perry had some coins. 45% of his coins were made up of 20-cent coins which was equal to the number of $1 coins. The rest of the coins were made up of 5-cent coins. Given that Perry had $17 more 20-cent coins than 5-cent coins, how many coins did Perry have altogether?
|
5-cent |
20-cent |
$1 |
Total |
Number |
2 u |
9 u |
9 u |
20 u |
Value |
5 |
20 |
100 |
|
Total value |
10 u |
180 u |
900 u |
|
45% =
45100 =
920The number of 20-cent coins and $1 coins is the same.
Number of 5-cent coins
= 20 u - 9 u - 9 u
= 2 u
$1 = 100¢
$17 x 100 = 17 x 100 = 1700¢
Number of more 20-cent coins than 5-cent coins
= 180 u - 10 u
= 170 u
170 u = 1700
1 u = 1700 ÷ 170 = 10
Total number of coins that Perry had
= 2 u + 9 u + 9 u
= 20 u
= 20 x 10
= 200
Answer(s): 200