Julian had some coins. 45% of his coins were made up of 20-cent coins which was equal to the number of $1 coins. The rest of the coins were made up of 10-cent coins. Given that Julian had $16 more 20-cent coins than 10-cent coins, how many coins did Julian have altogether?
| |
10-cent |
20-cent |
$1 |
Total |
| Number |
2 u |
9 u |
9 u |
20 u |
| Value |
10 |
20 |
100 |
|
| Total value |
20 u |
180 u |
900 u |
|
45% =
45100 =
920The number of 20-cent coins and $1 coins is the same.
Number of 10-cent coins
= 20 u - 9 u - 9 u
= 2 u
$1 = 100¢
$16 x 100 = 16 x 100 = 1600¢
Number of more 20-cent coins than 10-cent coins
= 180 u - 20 u
= 160 u
160 u = 1600
1 u = 1600 ÷ 160 = 10
Total number of coins that Julian had
= 2 u + 9 u + 9 u
= 20 u
= 20 x 10
= 200
Answer(s): 200
