Julian had some coins. 35% of his coins were made up of 20-cent coins which was equal to the number of $1 coins. The rest of the coins were made up of 10-cent coins. Given that Julian had $12 more 20-cent coins than 10-cent coins, how many coins did Julian have altogether?
|
10-cent |
20-cent |
$1 |
Total |
Number |
6 u |
7 u |
7 u |
20 u |
Value |
10 |
20 |
100 |
|
Total value |
60 u |
140 u |
700 u |
|
35% =
35100 =
720The number of 20-cent coins and $1 coins is the same.
Number of 10-cent coins
= 20 u - 7 u - 7 u
= 6 u
$1 = 100¢
$12 x 100 = 12 x 100 = 1200¢
Number of more 20-cent coins than 10-cent coins
= 140 u - 60 u
= 80 u
80 u = 1200
1 u = 1200 ÷ 80 = 15
Total number of coins that Julian had
= 6 u + 7 u + 7 u
= 20 u
= 20 x 15
= 300
Answer(s): 300