Lee had some coins. 45% of his coins were made up of 50-cent coins which was equal to the number of $1 coins. The rest of the coins were made up of 5-cent coins. Given that Lee had $110 more 50-cent coins than 5-cent coins, how many coins did Lee have altogether?
| |
5-cent |
50-cent |
$1 |
Total |
| Number |
2 u |
9 u |
9 u |
20 u |
| Value |
5 |
50 |
100 |
|
| Total value |
10 u |
450 u |
900 u |
|
45% =
45100 =
920The number of 50-cent coins and $1 coins is the same.
Number of 5-cent coins
= 20 u - 9 u - 9 u
= 2 u
$1 = 100¢
$110 x 100 = 110 x 100 = 11000¢
Number of more 50-cent coins than 5-cent coins
= 450 u - 10 u
= 440 u
440 u = 11000
1 u = 11000 ÷ 440 = 25
Total number of coins that Lee had
= 2 u + 9 u + 9 u
= 20 u
= 20 x 25
= 500
Answer(s): 500
