Henry had some coins. 35% of his coins were made up of 50-cent coins which was equal to the number of $1 coins. The rest of the coins were made up of 10-cent coins. Given that Henry had $29 more 50-cent coins than 10-cent coins, how many coins did Henry have altogether?
|
10-cent |
50-cent |
$1 |
Total |
Number |
6 u |
7 u |
7 u |
20 u |
Value |
10 |
50 |
100 |
|
Total value |
60 u |
350 u |
700 u |
|
35% =
35100 =
720The number of 50-cent coins and $1 coins is the same.
Number of 10-cent coins
= 20 u - 7 u - 7 u
= 6 u
$1 = 100¢
$29 x 100 = 29 x 100 = 2900¢
Number of more 50-cent coins than 10-cent coins
= 350 u - 60 u
= 290 u
290 u = 2900
1 u = 2900 ÷ 290 = 10
Total number of coins that Henry had
= 6 u + 7 u + 7 u
= 20 u
= 20 x 10
= 200
Answer(s): 200