Henry had some coins. 35% of his coins were made up of 20-cent coins which was equal to the number of $1 coins. The rest of the coins were made up of 5-cent coins. Given that Henry had $11 more 20-cent coins than 5-cent coins, how many coins did Henry have altogether?
| |
5-cent |
20-cent |
$1 |
Total |
| Number |
6 u |
7 u |
7 u |
20 u |
| Value |
5 |
20 |
100 |
|
| Total value |
30 u |
140 u |
700 u |
|
35% =
35100 =
720The number of 20-cent coins and $1 coins is the same.
Number of 5-cent coins
= 20 u - 7 u - 7 u
= 6 u
$1 = 100¢
$11 x 100 = 11 x 100 = 1100¢
Number of more 20-cent coins than 5-cent coins
= 140 u - 30 u
= 110 u
110 u = 1100
1 u = 1100 ÷ 110 = 10
Total number of coins that Henry had
= 6 u + 7 u + 7 u
= 20 u
= 20 x 10
= 200
Answer(s): 200
