There was an equal number of tables and stools in the morning. At 1 p.m., some tables were added and some stools were removed, resulting in the number of tables being increased by 20% while the number of stools decreased by 30%. At 7 p.m. the number of tables increased by 50%. If a total of 48 tables were added during the day, how many more tables than stools were there in the end?

At 1 p.m.	Tables	Stools
Before	1 u	1 u
Change	+ 0.2 u	- 0.3 u
After	1.2 u	0.7 u

At 7 p.m.	Tables	Stools
Before	1.2 u	0.7 u
Change	+ 0.6 u	No change
After	1.8 u	0.7 u

Number of tables added
= 20% x 1 u
= ²⁰₁₀₀ x 1 u
= 0.2 u

Number of stools removed
= 30% x 1 u 
= ³⁰₁₀₀ x 1 u
= 0.3 u

Number of tables increased by tables at 7 p.m.
= 50% x 1.2 u
= ⁵⁰₁₀₀ x 1.2 u
= 0.6 u

Number of tables added during the day
= 1.8 u - 1 u
= 0.8 u

0.8 u = 48

1 u = 48 ÷ 0.8 = 60

Number of more tables than stools in the end
= 1.8 u - 0.7 u
= 1.1 u
= 1.1 x 60
= 66

Answer(s): 66