There was an equal number of tables and desks in the morning. At 2 p.m., some tables were added and some desks were removed, resulting in the number of tables being increased by 20% while the number of desks decreased by 20%. At 5 p.m. the number of tables increased by 50%. If a total of 76 tables were added during the day, how many more tables than desks were there in the end?
At 2 p.m. |
Tables |
Desks |
Before |
1 u |
1 u |
Change |
+ 0.2 u |
- 0.2 u |
After |
1.2 u |
0.8 u |
At 5 p.m. |
Tables |
Desks |
Before |
1.2 u |
0.8 u |
Change |
+ 0.6 u |
No change |
After |
1.8 u |
0.8 u |
Number of tables added
= 20% x 1 u
=
20100 x 1 u
= 0.2 u
Number of desks removed
= 20% x 1 u
=
20100 x 1 u
= 0.2 u
Number of tables increased by tables at 5 p.m.
= 50% x 1.2 u
=
50100 x 1.2 u
= 0.6 u
Number of tables added during the day
= 1.8 u - 1 u
= 0.8 u
0.8 u = 76
1 u = 76 ÷ 0.8 = 95
Number of more tables than desks in the end
= 1.8 u - 0.8 u
= 1 u
= 1 x 95
= 95
Answer(s): 95