There was an equal number of chairs and tables in the morning. At 2 p.m., some chairs were added and some tables were removed, resulting in the number of chairs being increased by 20% while the number of tables decreased by 20%. At 6 p.m. the number of chairs increased by 50%. If a total of 52 chairs were added during the day, how many more chairs than tables were there in the end?

At 2 p.m.	Chairs	Tables
Before	1 u	1 u
Change	+ 0.2 u	- 0.2 u
After	1.2 u	0.8 u

At 6 p.m.	Chairs	Tables
Before	1.2 u	0.8 u
Change	+ 0.6 u	No change
After	1.8 u	0.8 u

Number of chairs added
= 20% x 1 u
= ²⁰₁₀₀ x 1 u
= 0.2 u

Number of tables removed
= 20% x 1 u 
= ²⁰₁₀₀ x 1 u
= 0.2 u

Number of chairs increased by chairs at 6 p.m.
= 50% x 1.2 u
= ⁵⁰₁₀₀ x 1.2 u
= 0.6 u

Number of chairs added during the day
= 1.8 u - 1 u
= 0.8 u

0.8 u = 52

1 u = 52 ÷ 0.8 = 65

Number of more chairs than tables in the end
= 1.8 u - 0.8 u
= 1 u
= 1 x 65
= 65

Answer(s): 65