There was an equal number of desks and chairs in the morning. At 1 p.m., some desks were added and some chairs were removed, resulting in the number of desks being increased by 20% while the number of chairs decreased by 40%. At 7 p.m. the number of desks increased by 50%. If a total of 80 desks were added during the day, how many more desks than chairs were there in the end?
At 1 p.m. |
Desks |
Chairs |
Before |
1 u |
1 u |
Change |
+ 0.2 u |
- 0.4 u |
After |
1.2 u |
0.6 u |
At 7 p.m. |
Desks |
Chairs |
Before |
1.2 u |
0.6 u |
Change |
+ 0.6 u |
No change |
After |
1.8 u |
0.6 u |
Number of desks added
= 20% x 1 u
=
20100 x 1 u
= 0.2 u
Number of chairs removed
= 40% x 1 u
=
40100 x 1 u
= 0.4 u
Number of desks increased by desks at 7 p.m.
= 50% x 1.2 u
=
50100 x 1.2 u
= 0.6 u
Number of desks added during the day
= 1.8 u - 1 u
= 0.8 u
0.8 u = 80
1 u = 80 ÷ 0.8 = 100
Number of more desks than chairs in the end
= 1.8 u - 0.6 u
= 1.2 u
= 1.2 x 100
= 120
Answer(s): 120