There was an equal number of chairs and desks in the morning. At 4 p.m., some chairs were added and some desks were removed, resulting in the number of chairs being increased by 20% while the number of desks decreased by 30%. At 9 p.m. the number of chairs increased by 50%. If a total of 40 chairs were added during the day, how many more chairs than desks were there in the end?
At 4 p.m. |
Chairs |
Desks |
Before |
1 u |
1 u |
Change |
+ 0.2 u |
- 0.3 u |
After |
1.2 u |
0.7 u |
At 9 p.m. |
Chairs |
Desks |
Before |
1.2 u |
0.7 u |
Change |
+ 0.6 u |
No change |
After |
1.8 u |
0.7 u |
Number of chairs added
= 20% x 1 u
=
20100 x 1 u
= 0.2 u
Number of desks removed
= 30% x 1 u
=
30100 x 1 u
= 0.3 u
Number of chairs increased by chairs at 9 p.m.
= 50% x 1.2 u
=
50100 x 1.2 u
= 0.6 u
Number of chairs added during the day
= 1.8 u - 1 u
= 0.8 u
0.8 u = 40
1 u = 40 ÷ 0.8 = 50
Number of more chairs than desks in the end
= 1.8 u - 0.7 u
= 1.1 u
= 1.1 x 50
= 55
Answer(s): 55