There was an equal number of desks and stools in the morning. At 3 p.m., some desks were added and some stools were removed, resulting in the number of desks being increased by 20% while the number of stools decreased by 30%. At 10 p.m. the number of desks increased by 50%. If a total of 40 desks were added during the day, how many more desks than stools were there in the end?
At 3 p.m. |
Desks |
Stools |
Before |
1 u |
1 u |
Change |
+ 0.2 u |
- 0.3 u |
After |
1.2 u |
0.7 u |
At 10 p.m. |
Desks |
Stools |
Before |
1.2 u |
0.7 u |
Change |
+ 0.6 u |
No change |
After |
1.8 u |
0.7 u |
Number of desks added
= 20% x 1 u
=
20100 x 1 u
= 0.2 u
Number of stools removed
= 30% x 1 u
=
30100 x 1 u
= 0.3 u
Number of desks increased by desks at 10 p.m.
= 50% x 1.2 u
=
50100 x 1.2 u
= 0.6 u
Number of desks added during the day
= 1.8 u - 1 u
= 0.8 u
0.8 u = 40
1 u = 40 ÷ 0.8 = 50
Number of more desks than stools in the end
= 1.8 u - 0.7 u
= 1.1 u
= 1.1 x 50
= 55
Answer(s): 55