There was an equal number of chikoos and guavas. On Monday, some chikoos were added, such that the number of chikoos increased by 60%. On Tuesday, the number of chikoos further increased by 50% and the number of guavas decreased by 20%. There were 128 more chikoos than guavas in the end. How many chikoos and guavas were there altogether at first?

	Chikoos	Guavas
Before	1 u	1 u
Change 1	+ 0.6 u	No change
After 1	1.6 u	1 u
Change 2	+ 0.8 u	- 0.2 u
After 2	2.4 u	0.8 u

Number of chikoos added on Monday
= 60% x 1 u
= ⁶⁰₁₀₀ x 1 u
= 0.6 u

Number of chikoos increased on Tuesday
= 50% x 1.6 u
= ⁵⁰₁₀₀ x 1.6 u
= 0.8 u

Number of guavas decreased on Tuesday
= 20% x 1 u
= ²⁰₁₀₀ x 1 u
= 0.2 u

Number of more chikoos than guavas in the end
= 2.4 u - 0.8 u
= 1.6 u

1.6 u = 128

1 u = 128 ÷ 1.6 = 80

Total number of chikoos and guavas at first
= 1 u + 1 u
= 2 u
= 2 x 80
= 160

Answer(s): 160