There was an equal number of pears and guavas. On Friday, some pears were added, such that the number of pears increased by 80%. On Saturday, the number of pears further increased by 50% and the number of guavas decreased by 20%. There were 57 more pears than guavas in the end. How many pears and guavas were there altogether at first?

	Pears	Guavas
Before	1 u	1 u
Change 1	+ 0.8 u	No change
After 1	1.8 u	1 u
Change 2	+ 0.9 u	- 0.2 u
After 2	2.7 u	0.8 u

Number of pears added on Friday
= 80% x 1 u
= ⁸⁰₁₀₀ x 1 u
= 0.8 u

Number of pears increased on Saturday
= 50% x 1.8 u
= ⁵⁰₁₀₀ x 1.8 u
= 0.9 u

Number of guavas decreased on Saturday
= 20% x 1 u
= ²⁰₁₀₀ x 1 u
= 0.2 u

Number of more pears than guavas in the end
= 2.7 u - 0.8 u
= 1.9 u

1.9 u = 57

1 u = 57 ÷ 1.9 = 30

Total number of pears and guavas at first
= 1 u + 1 u
= 2 u
= 2 x 30
= 60

Answer(s): 60