There was an equal number of chikoos and dragonfruits. On Thursday, some chikoos were added, such that the number of chikoos increased by 60%. On Friday, the number of chikoos further increased by 50% and the number of dragonfruits decreased by 10%. There were 105 more chikoos than dragonfruits in the end. How many chikoos and dragonfruits were there altogether at first?

	Chikoos	Dragonfruits
Before	1 u	1 u
Change 1	+ 0.6 u	No change
After 1	1.6 u	1 u
Change 2	+ 0.8 u	- 0.1 u
After 2	2.4 u	0.9 u

Number of chikoos added on Thursday
= 60% x 1 u
= ⁶⁰₁₀₀ x 1 u
= 0.6 u

Number of chikoos increased on Friday
= 50% x 1.6 u
= ⁵⁰₁₀₀ x 1.6 u
= 0.8 u

Number of dragonfruits decreased on Friday
= 10% x 1 u
= ¹⁰₁₀₀ x 1 u
= 0.1 u

Number of more chikoos than dragonfruits in the end
= 2.4 u - 0.9 u
= 1.5 u

1.5 u = 105

1 u = 105 ÷ 1.5 = 70

Total number of chikoos and dragonfruits at first
= 1 u + 1 u
= 2 u
= 2 x 70
= 140

Answer(s): 140