There was an equal number of pears and chikoos. On Tuesday, some pears were added, such that the number of pears increased by 60%. On Wednesday, the number of pears further increased by 50% and the number of chikoos decreased by 30%. There were 136 more pears than chikoos in the end. How many pears and chikoos were there altogether at first?
|
Pears |
Chikoos |
Before |
1 u |
1 u |
Change 1 |
+ 0.6 u |
No change |
After 1 |
1.6 u |
1 u |
Change 2 |
+ 0.8 u |
- 0.3 u |
After 2 |
2.4 u |
0.7 u |
Number of pears added on Tuesday
= 60% x 1 u
=
60100 x 1 u
= 0.6 u
Number of pears increased on Wednesday
= 50% x 1.6 u
=
50100 x 1.6 u
= 0.8 u
Number of chikoos decreased on Wednesday
= 30% x 1 u
=
30100 x 1 u
= 0.3 u
Number of more pears than chikoos in the end
= 2.4 u - 0.7 u
= 1.7 u
1.7 u = 136
1 u = 136 ÷ 1.7 = 80
Total number of pears and chikoos at first
= 1 u + 1 u
= 2 u
= 2 x 80
= 160
Answer(s): 160