There was an equal number of chikoos and persimmons. On Thursday, some chikoos were added, such that the number of chikoos increased by 80%. On Friday, the number of chikoos further increased by 50% and the number of persimmons decreased by 10%. There were 36 more chikoos than persimmons in the end. How many chikoos and persimmons were there altogether at first?
|
Chikoos |
Persimmons |
Before |
1 u |
1 u |
Change 1 |
+ 0.8 u |
No change |
After 1 |
1.8 u |
1 u |
Change 2 |
+ 0.9 u |
- 0.1 u |
After 2 |
2.7 u |
0.9 u |
Number of chikoos added on Thursday
= 80% x 1 u
=
80100 x 1 u
= 0.8 u
Number of chikoos increased on Friday
= 50% x 1.8 u
=
50100 x 1.8 u
= 0.9 u
Number of persimmons decreased on Friday
= 10% x 1 u
=
10100 x 1 u
= 0.1 u
Number of more chikoos than persimmons in the end
= 2.7 u - 0.9 u
= 1.8 u
1.8 u = 36
1 u = 36 ÷ 1.8 = 20
Total number of chikoos and persimmons at first
= 1 u + 1 u
= 2 u
= 2 x 20
= 40
Answer(s): 40