There was an equal number of persimmons and kiwis. On Wednesday, some persimmons were added, such that the number of persimmons increased by 80%. On Thursday, the number of persimmons further increased by 50% and the number of kiwis decreased by 30%. There were 180 more persimmons than kiwis in the end. How many persimmons and kiwis were there altogether at first?

	Persimmons	Kiwis
Before	1 u	1 u
Change 1	+ 0.8 u	No change
After 1	1.8 u	1 u
Change 2	+ 0.9 u	- 0.3 u
After 2	2.7 u	0.7 u

Number of persimmons added on Wednesday
= 80% x 1 u
= ⁸⁰₁₀₀ x 1 u
= 0.8 u

Number of persimmons increased on Thursday
= 50% x 1.8 u
= ⁵⁰₁₀₀ x 1.8 u
= 0.9 u

Number of kiwis decreased on Thursday
= 30% x 1 u
= ³⁰₁₀₀ x 1 u
= 0.3 u

Number of more persimmons than kiwis in the end
= 2.7 u - 0.7 u
= 2 u

2 u = 180

1 u = 180 ÷ 2 = 90

Total number of persimmons and kiwis at first
= 1 u + 1 u
= 2 u
= 2 x 90
= 180

Answer(s): 180