There was an equal number of pears and chikoos. On Wednesday, some pears were added, such that the number of pears increased by 80%. On Thursday, the number of pears further increased by 50% and the number of chikoos decreased by 20%. There were 57 more pears than chikoos in the end. How many pears and chikoos were there altogether at first?
|
Pears |
Chikoos |
Before |
1 u |
1 u |
Change 1 |
+ 0.8 u |
No change |
After 1 |
1.8 u |
1 u |
Change 2 |
+ 0.9 u |
- 0.2 u |
After 2 |
2.7 u |
0.8 u |
Number of pears added on Wednesday
= 80% x 1 u
=
80100 x 1 u
= 0.8 u
Number of pears increased on Thursday
= 50% x 1.8 u
=
50100 x 1.8 u
= 0.9 u
Number of chikoos decreased on Thursday
= 20% x 1 u
=
20100 x 1 u
= 0.2 u
Number of more pears than chikoos in the end
= 2.7 u - 0.8 u
= 1.9 u
1.9 u = 57
1 u = 57 ÷ 1.9 = 30
Total number of pears and chikoos at first
= 1 u + 1 u
= 2 u
= 2 x 30
= 60
Answer(s): 60