There was an equal number of peaches and pears. On Tuesday, some peaches were added, such that the number of peaches increased by 60%. On Wednesday, the number of peaches further increased by 50% and the number of pears decreased by 30%. There were 102 more peaches than pears in the end. How many peaches and pears were there altogether at first?

	Peaches	Pears
Before	1 u	1 u
Change 1	+ 0.6 u	No change
After 1	1.6 u	1 u
Change 2	+ 0.8 u	- 0.3 u
After 2	2.4 u	0.7 u

Number of peaches added on Tuesday
= 60% x 1 u
= ⁶⁰₁₀₀ x 1 u
= 0.6 u

Number of peaches increased on Wednesday
= 50% x 1.6 u
= ⁵⁰₁₀₀ x 1.6 u
= 0.8 u

Number of pears decreased on Wednesday
= 30% x 1 u
= ³⁰₁₀₀ x 1 u
= 0.3 u

Number of more peaches than pears in the end
= 2.4 u - 0.7 u
= 1.7 u

1.7 u = 102

1 u = 102 ÷ 1.7 = 60

Total number of peaches and pears at first
= 1 u + 1 u
= 2 u
= 2 x 60
= 120

Answer(s): 120