There was an equal number of peaches and persimmons. On Wednesday, some peaches were added, such that the number of peaches increased by 60%. On Thursday, the number of peaches further increased by 50% and the number of persimmons decreased by 20%. There were 144 more peaches than persimmons in the end. How many peaches and persimmons were there altogether at first?
|
Peaches |
Persimmons |
Before |
1 u |
1 u |
Change 1 |
+ 0.6 u |
No change |
After 1 |
1.6 u |
1 u |
Change 2 |
+ 0.8 u |
- 0.2 u |
After 2 |
2.4 u |
0.8 u |
Number of peaches added on Wednesday
= 60% x 1 u
=
60100 x 1 u
= 0.6 u
Number of peaches increased on Thursday
= 50% x 1.6 u
=
50100 x 1.6 u
= 0.8 u
Number of persimmons decreased on Thursday
= 20% x 1 u
=
20100 x 1 u
= 0.2 u
Number of more peaches than persimmons in the end
= 2.4 u - 0.8 u
= 1.6 u
1.6 u = 144
1 u = 144 ÷ 1.6 = 90
Total number of peaches and persimmons at first
= 1 u + 1 u
= 2 u
= 2 x 90
= 180
Answer(s): 180