There was an equal number of pomegranates and pears. On Wednesday, some pomegranates were added, such that the number of pomegranates increased by 60%. On Thursday, the number of pomegranates further increased by 50% and the number of pears decreased by 30%. There were 153 more pomegranates than pears in the end. How many pomegranates and pears were there altogether at first?
|
Pomegranates |
Pears |
Before |
1 u |
1 u |
Change 1 |
+ 0.6 u |
No change |
After 1 |
1.6 u |
1 u |
Change 2 |
+ 0.8 u |
- 0.3 u |
After 2 |
2.4 u |
0.7 u |
Number of pomegranates added on Wednesday
= 60% x 1 u
=
60100 x 1 u
= 0.6 u
Number of pomegranates increased on Thursday
= 50% x 1.6 u
=
50100 x 1.6 u
= 0.8 u
Number of pears decreased on Thursday
= 30% x 1 u
=
30100 x 1 u
= 0.3 u
Number of more pomegranates than pears in the end
= 2.4 u - 0.7 u
= 1.7 u
1.7 u = 153
1 u = 153 ÷ 1.7 = 90
Total number of pomegranates and pears at first
= 1 u + 1 u
= 2 u
= 2 x 90
= 180
Answer(s): 180