There was an equal number of kiwis and pears. On Monday, some kiwis were added, such that the number of kiwis increased by 60%. On Tuesday, the number of kiwis further increased by 50% and the number of pears decreased by 30%. There were 85 more kiwis than pears in the end. How many kiwis and pears were there altogether at first?

	Kiwis	Pears
Before	1 u	1 u
Change 1	+ 0.6 u	No change
After 1	1.6 u	1 u
Change 2	+ 0.8 u	- 0.3 u
After 2	2.4 u	0.7 u

Number of kiwis added on Monday
= 60% x 1 u
= ⁶⁰₁₀₀ x 1 u
= 0.6 u

Number of kiwis increased on Tuesday
= 50% x 1.6 u
= ⁵⁰₁₀₀ x 1.6 u
= 0.8 u

Number of pears decreased on Tuesday
= 30% x 1 u
= ³⁰₁₀₀ x 1 u
= 0.3 u

Number of more kiwis than pears in the end
= 2.4 u - 0.7 u
= 1.7 u

1.7 u = 85

1 u = 85 ÷ 1.7 = 50

Total number of kiwis and pears at first
= 1 u + 1 u
= 2 u
= 2 x 50
= 100

Answer(s): 100