There are 10% as many blue balls as silver balls in Hazel's collection of balls. The number of red balls is 40% fewer than the number of silver balls. There are 315 more red balls than blue balls.

1. Find the total number of balls in the collection.
2. What percentage are the number of silver balls as compared to the number of red balls? Leave your answer as a mixed number in its simplest form.

Blue	Silver	Red
1x1	10x1
	5x2	3x2
1 u	10 u	6 u

(a)
10% = ¹⁰₁₀₀ = ¹₁₀

100% - 40% = 60%
60% = ⁶⁰₁₀₀ = ³₅

The number of silver balls is the repeated identity. Make the number of silver balls the same.  LCM of 10 and 5 is 10.

Number of more red balls than blue balls
= 6 u - 1 u
= 5 u

5 u = 315

1 u = 315 ÷ 5 = 63

Total number of balls in the collection
= 1 u + 10 u + 6 u 
= 17 u
= 17 x 63
= 1071

(b)
Percentage of the number of silver balls as compared to the number of red balls
= ⁵₃ x 100%
= ⁵⁰⁰₃ %
= 166²₃ %

Answer(s): (a) 1071; (b) 166²₃ %