In a boutique that sells windbreakers, 506 white windbreakers were sold and 10% of the remaining windbreakers that were sold were green. Of the leftover, 60% of the windbreakers sold were brown windbreakers and the rest were gold windbreakers. Given that the number of gold windbreakers sold was 25% of the total number of windbreakers sold, how many green and gold windbreakers were sold altogether?
10% =
10100 =
110 60% =
60100 =
35 25% =
25100 =
14
| White |
Green |
Brown |
Gold |
| 506 |
1x5 |
9x5 |
| |
|
3x9 |
2x9 |
| 3x18 |
1x18 |
| 22 u |
5 u |
27 u |
18 u |
The total number of brown and gold shirts is the combined repeated identity. Make the total number of brown and gold shirts the same. LCM of 9 and 5 is 45.
The number of gold shirts is repeated. Make the number of gold shirts the same. LCM of 18 and 1 is 18.
Number of white windbreakers
= 54 u - 5 u - 27 u
= 22 u
22 u = 506
1 u = 506 ÷ 22 = 23
Number of green and gold windbreakers
= 5 u + 18 u
= 23 u
= 23 x 23
= 529
Answer(s): 529
