In a kiosk that sells windbreakers, 14 black windbreakers were sold and 25% of the remaining windbreakers that were sold were white. Of the leftover, 50% of the windbreakers sold were red windbreakers and the rest were gold windbreakers. Given that the number of gold windbreakers sold was 20% of the total number of windbreakers sold, how many white and gold windbreakers were sold altogether?
25% =
25100 =
14 50% =
50100 =
12 20% =
20100 =
15
| Black |
White |
Red |
Gold |
| 14 |
1x2 |
3x2 |
| |
|
1x3 |
1x3 |
| 4x3 |
1x3 |
| 7 u |
2 u |
3 u |
3 u |
The total number of red and gold shirts is the combined repeated identity. Make the total number of red and gold shirts the same. LCM of 3 and 2 is 6.
The number of gold shirts is repeated. Make the number of gold shirts the same. LCM of 3 and 1 is 3.
Number of black windbreakers
= 12 u - 2 u - 3 u
= 7 u
7 u = 14
1 u = 14 ÷ 7 = 2
Number of white and gold windbreakers
= 2 u + 3 u
= 5 u
= 5 x 2
= 10
Answer(s): 10
