In a shop that sells windbreakers, 70 black windbreakers were sold and 50% of the remaining windbreakers that were sold were grey. Of the leftover, 40% of the windbreakers sold were yellow windbreakers and the rest were green windbreakers. Given that the number of green windbreakers sold was 20% of the total number of windbreakers sold, how many grey and green windbreakers were sold altogether?
50% =
50100 =
12 40% =
40100 =
25 20% =
20100 =
15
| Black |
Grey |
Yellow |
Green |
| 70 |
1x5 |
1x5 |
| |
|
2x1 |
3x1 |
| 4x3 |
1x3 |
| 5 u |
5 u |
2 u |
3 u |
The total number of yellow and green shirts is the combined repeated identity. Make the total number of yellow and green shirts the same. LCM of 1 and 5 is 5.
The number of green shirts is repeated. Make the number of green shirts the same. LCM of 3 and 1 is 3.
Number of black windbreakers
= 12 u - 5 u - 2 u
= 5 u
5 u = 70
1 u = 70 ÷ 5 = 14
Number of grey and green windbreakers
= 5 u + 3 u
= 8 u
= 8 x 14
= 112
Answer(s): 112
