In a mall that sells blazers, 3680 grey blazers were sold and 10% of the remaining blazers that were sold were black. Of the leftover, 50% of the blazers sold were purple blazers and the rest were brown blazers. Given that the number of brown blazers sold was 5% of the total number of blazers sold, how many black and grey blazers were sold altogether?
10% =
10100 =
110 50% =
50100 =
12 5% =
5100 =
120
| Grey |
Black |
Purple |
Brown |
| 3680 |
1x2 |
9x2 |
| |
|
1x9 |
1x9 |
| 19x9 |
1x9 |
| 160 u |
2 u |
9 u |
9 u |
The total number of purple and brown shirts is the combined repeated identity. Make the total number of purple and brown shirts the same. LCM of 9 and 2 is 18.
The number of brown shirts is repeated. Make the number of brown shirts the same. LCM of 9 and 1 is 9.
Number of grey blazers
= 171 u - 2 u - 9 u
= 160 u
160 u = 3680
1 u = 3680 ÷ 10 = 23
Number of black and grey blazers
= 2 u + 3680
= 2 x 23 + 3680
= 46 + 3680
= 3726
Answer(s): 3726
