In a kiosk that sells windbreakers, 308 silver windbreakers were sold and 10% of the remaining windbreakers that were sold were blue. Of the leftover, 60% of the windbreakers sold were gold windbreakers and the rest were green windbreakers. Given that the number of green windbreakers sold was 25% of the total number of windbreakers sold, how many blue and silver windbreakers were sold altogether?
10% = ¹⁰₁₀₀ = ¹₁₀
60% = ⁶⁰₁₀₀ = ³₅
25% = ²⁵₁₀₀ = ¹₄

Silver	Blue	Gold	Green
308	1x5	9x5
		3x9	2x9
3x18			1x18
22 u	5 u	27 u	18 u

The total number of gold and green shirts is the combined repeated identity. Make the total number of gold and green shirts the same. LCM of 9 and 5 is 45.

The number of green shirts is repeated. Make the number of green shirts the same. LCM of 18 and 1 is 18.

Number of silver windbreakers
= 54 u - 5 u - 27 u
= 22 u

22 u = 308

1 u = 308 ÷ 22 = 14

Number of blue and silver windbreakers
= 5 u + 308
= (5 x 14) + 308
= 70 + 308
= 378

Answer(s): 378