In a shop that sells windbreakers, 48 white windbreakers were sold and 50% of the remaining windbreakers that were sold were silver. Of the leftover, 40% of the windbreakers sold were black windbreakers and the rest were blue windbreakers. Given that the number of blue windbreakers sold was 25% of the total number of windbreakers sold, how many silver and white windbreakers were sold altogether?
50% = ⁵⁰₁₀₀ = ¹₂
40% = ⁴⁰₁₀₀ = ²₅
25% = ²⁵₁₀₀ = ¹₄

White	Silver	Black	Blue
48	1x5	1x5
		2x1	3x1
3x3			1x3
2 u	5 u	2 u	3 u

The total number of black and blue shirts is the combined repeated identity. Make the total number of black and blue shirts the same. LCM of 1 and 5 is 5.

The number of blue shirts is repeated. Make the number of blue shirts the same. LCM of 3 and 1 is 3.

Number of white windbreakers
= 9 u - 5 u - 2 u
= 2 u

2 u = 48

1 u = 48 ÷ 2 = 24

Number of silver and white windbreakers
= 5 u + 48
= (5 x 24) + 48
= 120 + 48
= 168

Answer(s): 168