In a shopping centre that sells windbreakers, 696 gold windbreakers were sold and 10% of the remaining windbreakers that were sold were yellow. Of the leftover, 40% of the windbreakers sold were black windbreakers and the rest were blue windbreakers. Given that the number of blue windbreakers sold was 25% of the total number of windbreakers sold, how many yellow and blue windbreakers were sold altogether?
10% =
10100 =
110 40% =
40100 =
25 25% =
25100 =
14
| Gold |
Yellow |
Black |
Blue |
| 696 |
1x5 |
9x5 |
| |
|
2x9 |
3x9 |
| 3x27 |
1x27 |
| 58 u |
5 u |
18 u |
27 u |
The total number of black and blue shirts is the combined repeated identity. Make the total number of black and blue shirts the same. LCM of 9 and 5 is 45.
The number of blue shirts is repeated. Make the number of blue shirts the same. LCM of 27 and 1 is 27.
Number of gold windbreakers
= 81 u - 5 u - 18 u
= 58 u
58 u = 696
1 u = 696 ÷ 58 = 12
Number of yellow and blue windbreakers
= 5 u + 27 u
= 32 u
= 32 x 12
= 384
Answer(s): 384
